(x^2+1)=^5

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Solution for (x^2+1)=^5 equation: 



(x^2+1)=^5

We move all terms to the left:

(x^2+1)-(^5)=0

We add all the numbers together, and all the variables

(x^2+1)=0

We get rid of parentheses

x^2+1=0

a = 1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·1·1
Δ = -4
Delta is less than zero, so there is no solution for the equation

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